struct MyStruct
{
public int X { get; set; }
public int Y { get; set; }
public MyStruct(int x, int y)
{
this.X = x;
this.Y = y;
}
}
Will trigger an error on line 8:
The ‘this’ object cannot be used before all of its fields are assigned to
So I thought I might fix it by assigning a value to the fields. Since we have automatic properties, let’s convert them to normal properties:
struct MyStruct
{
private int _x = 0;
public int X
{
get
{
return _x;
}
set
{
_x = value;
}
}
private int _y = 0;
public int Y
{
get
{
return _y;
}
set
{
_y = value;
}
}
public MyStruct(int x, int y)
{
this.X = x;
this.Y = y;
}
}
Let’s press F5. Oeh noes, another error:
‘MyStruct._x’ cannot have its instance field initializers in structs
So you can’t do field initialization in a struct (apart from in a function / constructor / getter / setter).
Let’s go back to the first piece of code and make it work by adding 7 characters:
struct MyStruct
{
public int X { get; set; }
public int Y { get; set; }
public MyStruct(int x, int y) : this()
{
this.X = x;
this.Y = y;
}
}
The this() initializes the struct, and in the constructor itself the struct’s vars & properties are set to their default values. It’s weird though that an int needs initialization…
Entries (RSS)
That’s because a struct is a value type and is placed on the stack. You can look at a struct as a collection of variables which needs to be available when instantiated. All methods are only available when all public variables are set. Getters and setters are methods as well.